Consider the picture given below, we can divide the circle into two part by using the line AB, the area of the two portions are same.
That is we get the total area by multiplying area of the sector by 2.
We can find out the area of part above the line AB .
Given AB = 2cm
Circles having equal
radius. So,
AC = BC = 2 cm.
ABC is an equilateral triangle so angles are 60° each.
Add the area of sectors having centre A and B.
The area of ΔABC include twice, so we will subtract it once.
Area of sectors having centre A
Area of sectors having centre B
Area of ΔABC
Area of the part above the line AB = 2.09 + 2.09 – 1.7 = 2.45 cm2
The area of the region common to both = 2 × 2.45 = 4.90 cm2
