Equivalent circuit can be soon as :
Line 1 : For 4 μF and 2 μF, they are in series
∴Ceq = \(\frac{4\times2}{4+2}\) = \(\frac{8}{6}\) = \(\frac{4}{3}\)μF
∴ Q1 = Ceq.V = \(\frac{4}{3}\)x 5 = \(\frac{20}{3}\) μc
Line 3 : Ceq = \(\frac{2\times2}{2\times2}\) = 1μF
Q2 = Ceq.V = 1 x 5 = 5μc
∴ Total charge in capacitors = \(\frac{20}{3}\times5\) = \(\frac{35}{3}\)μc