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in CBSE by (15 points)
find the square root of 37845

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1 Answer

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by (215 points)
\( \sqrt{37845}=\sqrt{3^2 \times 5 \times 29^2} \)

\( \sqrt{3^2 \times 5 \times 29^2}=\sqrt{3^2} \sqrt{5} \sqrt{29^2} \)

\( \sqrt{3^2} \sqrt{5} \sqrt{29^2}=3 \times \sqrt{5} \times 29=87 \sqrt{5} \)

we know \( \sqrt{5}=2.23606 \) thus:

\( \sqrt{37845}=87 \times 2.23606=194.537 \)

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