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Compound X on reduction with `LiAlH_(4)` gives a hydride Y containing 21.72% hydrogen and other products. The compound Y reacts with air expolosively resulting in boron trioxide. What are X and Y respectively ?
A. `BCl_(3), B_(2)H_(6)`
B. `PCl_(3), B_(2)H_(6)`
C. `B_(2)H_(6), BCl_(3)`
D. `LiAlH_(4),PCl_(3)`

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Correct Answer - A
The reaction scheme is
image
From the reaction scheme and the properties, it is clear that the compound Y is boron hydride. The boron hydride that contains 21.72% hydrogen is `B_(2)H_(6)`. So, Y is `B_(2)H_(6)` (dibrorane). `B_(2)H_(6)` is obtained by the reduction of `BCl_(3)` by `LiAlH_(4)`. So, X is `BCl_(3)`.
Reactions : `underset((X))(4BCl_(3))+3LiAlH_(4)rarr 3LiCl+underset((Y))(2B_(2)H_(6))+3AlCl_(3)`
`underset((Y))(B_(2)H_(6))+underset("from air")(3O_(2))overset("explosive")rarr B_(2)O_(3)+3H_(2)O`

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