Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
915 views
in Physics by (40.0k points)
closed by

Calculate the rise of water inside a clean glass capillary tube of radius 0.1 mm, when immersed in water of surface tension 7 × 10-2 N/m. The angle of contact between water and glass is zero, density of water = 1000 kg/m3 , g = 9.8 m/s2.

1 Answer

+1 vote
by (41.2k points)
selected by
 
Best answer

Data : r = 0.1 mm = 1 × 10-4 m, θ = 0°, T = 7 × 10-2 N/m, r = 103 kg/m , g = 9.8 m/s2 cos θ = cos 0° = 1

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...