Correct Answer - `-9.1555 kj`
`= 3.7 kJ mol^(-1) = 3700 J mol^(-1)`
`Delta H_("dissolution") = Delta h_(("ionisation")) + Delta H_(("hydration")) = 778 - 774.3`
`Delta S_("disolution") = 43 J mol^(-1)`
`Delta G_("disolution") = Delta H - T Delta S = 3700 - 298 X 43 = -9114 J, Delta G = - 9.114 kJ`