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The enthalpy of combustionof 1 mole of `H_(2)` to form `H_(2)O(l)` is`"…........."` kJ whereas to form `H_(2)O(g), ` it is `"…....................."`

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The enthalpy of combustionof 1 mole of `H_(2)` to form `H_(2)O(l)` is`"…........."` kJ whereas to form `H_(2)O(g), ` it is `"…....................."` kJ.
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Correct Answer - `285.8 kJ,241.8 kJ`
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