Question

The equilibrium constant for a reaction is 10.What will be thevalue of `DeltaG^(@) ` ? ` R=8.314 JK^(-1)mol^(-1) , T = 300 K `.

Answer 1

`DeltaG^(@) =-2.303 RT log K=-2.303 xx 8.314 JK^(-1) JK^(-1) mol^(-1) xx300 K xxlog10 = -5744.1 J`