Question

Which quantity out of `Delta_(r)G` and`Delta_(r)G^(c-)` will be zero at equilibrium ?

Answer 1

`Delta_(r)G= Delta_(r)G^(@) + RT ln K`. When reaction attains equilibrium `Delta_(r) G=0` so that`Delta_(r)G^(@)=- RT` ln K . Thus `Delta_(r)G^(@) =0` only when `K+1` . For all other values of `K, Delta_(r)G^(@) ` will be non-zero.