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A hypothetical electromagnetic wave is shown in figure. Find out the wavelength of the radiation.

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A hypothetical electromagnetic wave is shown in figure. Find out the wavelength of the radiation.
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Wavelength in the distance between two successive peaks or two successive throughs of a wave.
Therefore, `lambda=4xx2.16pm=8.64pm`
`=8.64xx10^(-12) [because 1"pm"=10^(-12)m]`
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