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An atom of an element contains `29` electrons and `35` neutrons. Deduce
a. The number of protons and
b. The elctonic configuration of the element.

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No. of protons in a neutral atom = No. of electrons = 29
Electronic configuration = `1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 3d^(10) 4s^(1)`.

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