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Nickel atom can lose two electrons to form `Ni^(2+)` ion. The atomic number of nickel is 28. From which orbital will nickel lose two electrons?

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The electronic configuration of Ni (Z = 28) is `[Ar] 3d^(8) 4s^(2)`. Nickel atom will lose 4s electrons to form `Ni^(2+)`ion with configuration `[Ar] 3d^(8)`.

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