LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
32 views
in Chemistry by (70.0k points)
closed by
The wavelength of the electron emitted, when in a hydrogen atom, electron falls from infinity to stationary state 1, would be (Rydberg constant `= 1.097 xx 10^(7) m^(-1)`)
A. 91 nm
B. 192 nm
C. 406 nm
D. `9.1 xx 10^(-8) nm`

1 Answer

0 votes
by (66.9k points)
selected by
 
Best answer
Correct Answer - A
`bar(v) = (1)/(lamda) = R ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))`
`= 1.097 xx 10^(7) m^(-1) ((1)/(1^(2)) - (1)/(oo^(2)))`
`= 1.097 xx 10^(7) m^(-1)`
or `lamda = (1)/(1.097 xx 10^(7)) m = 0.91 xx 10^(-7) m = 91 nm`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...