Question

To which orbit the electron in the hydrogen atom will jump on absorbing `12.1 eV` of energy?

Answer 1

Energy of electron in the nth orbit of H-atom is `E_(n) = (-13.6)/(n^(2)) eV :. E_(1) = -13.6 eV`
After absorbing 12.1 eV, the energy will be `= -13.6 + 12.1 eV = -1.5 eV`
Thus, `(-13.6)/(n^(2)) = - 1.5 eV or n^(2) = 9 or n = 3`
Thus, electron will jump to 3rd orbit.