Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.1k views
in Chemistry by (70.1k points)
closed by
Calculate the ratio between the wavelength of an electron and a proton if the proton is moving with half the velocity of electron (mass of proton `= 1.67 xx 10^(-27)kg` and mass of electron `= 9.11 xx 10^(-31) kg`)

1 Answer

0 votes
by (67.0k points)
selected by
 
Best answer
Correct Answer - 916.6
`lamda_(e) = (h)/(m_(e) v_(e)), lamda_(p) = (h)/(m_(p) v_(p)), (lamda_(e))/(lamda_(p)) = (m_(p) v_(p))/(m_(e) v_(e)) = (1)/(2) xx (1.67 xx 10^(-27) kg)/(9.11 xx 10^(-31) kg) = 916.6`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...