Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
670 views
in Chemistry by (70.3k points)
closed by
A proton is accelerated to a velocity of ` 3xx 10^(7) m s^(-1)`. If the velocity can be measured with a precision of `+- 0.5%`, calculate the uncertainty in position of proton [`h = 6.6 xx 10^(-34)Js`, mass of proton `= 1.66 xx 10^(-27)kg`]

1 Answer

0 votes
by (67.1k points)
selected by
 
Best answer
Correct Answer - `2.11 xx 10^(-13) m`
`Delta v = (0.5)/(100) xx (3 xx 10^(7)) ms^(-1) = 1.5 xx 10^(5) m s^(-1)`
`Delta x = (h)/(4pi m Delta v) = (6.6 xx 10^(-34) kg m^(2) s^(-1))/(4 xx 3.14 xx 1.66 xx 10^(-27) kg xx 1.5 xx 10^(5) ms^(-1)) = 2.11 xx 10^(-13) m`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...