Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
100 views
in Chemistry by (70.1k points)
closed by
An element occurs in the body centred cubic alttic with cell edge of 300 pm. The density of the element is `8.0 g//cm^(3)`. Answer the following
the distance fo closest approach between the two atoms of the element in the lattics is
A. 260 pm
B. 300 pm
C. 600 pm
D. 150 pm

1 Answer

0 votes
by (67.0k points)
selected by
 
Best answer
Correct Answer - A
Distance of closest approch in bcc `=(sqrt(3)a)/(2)`
`=(sqrt(3)x300)/(2)=260`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...