Taking the mass of the Earth as (about) 6 × 1024 kg, and the linear speed of the earth around the Sun as (about) 3 × 104 m/s, we have, the de Brogue wave length of the Earth as
λ = \(\cfrac{h}p\) = \(\cfrac{h}{M_e}\) = \(\cfrac{6.63\times10^{-34}J.s}{(6\times10^{24}kg)(3\times10^4m/s)}\)
= 3.683 × 10-63 m (extremely small)
