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in Linear Equations by (49.3k points)
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In a cooperative society, the number of men is thrice the number of women 29 women and 16 men more joined the society and now the number of men is double the number of women. How many women were there in the society at first?

1 Answer

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Best answer

Let the number of women = x

No of men = 3 x

No. of women when 29 more were joined = x + 29

No. of men when 16 more were joined = 3x + 16

3 x + 16 = 2 (x + 29)

3x + 16 = 2x + 58

3x – 2x = 58 – 16

x = 42

No. of women = 42;

No. of men = 3 × 42 = 126

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