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The volume of 10 vol `H_(2)O_(2)` required to liberate 500 `cm^(3)` of `O_(2)` at STP

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The volume of 10 vol `H_(2)O_(2)` required to liberate 500 `cm^(3)` of `O_(2)` at STP
A. 50 ml
B. `5*0 ml`
C. 15 ml
D. 100 ml.
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Correct Answer - A
10 ml of `O_(2)` is obtained at STP from `H_(2)O_(2)=1` ml 500 ml of `O_(2)` is obtained at STP from `H_(2)O_(2)=1//10xx500=50` mL.
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