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`H_(2)O_(2)` can be obtained when following reacts with `H_(2)SO_(4)` excepts with
A. `PbO_(2)`
B. `BaO_(2)`
C. `Na_(2)O_(2)`
D. `SrO_(2)`

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Correct Answer - a
`BaO_(2)+` dil. `H_(2)SO_(4) rarr BaSO_(4)+H_(2)O_(2)`
`Na_(2)O_(2)+` dil. `H_(2)SO_(4) rarr Na_(2)SO_(4)+H_(2)O_(2)`
`SrO_(2)+`dil. `H_(2)SO_(4) rarrSrSO_(4)+H_(2)o_(2)`
`PbO_(2)+` dil`H_(2)SO_(4) rarr PbSO_(4)+H_(2)O+(1)/(2)O_(2)uarr`
`PbO_(2)+H_(2)SO_(4)` cannot give `H_(2)O_(2)` , instead of it gives `H_(2)O+(1)/(2) uarr`.

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