LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
23 views
in Chemistry by (62.6k points)
closed by
Write down the acyclic isomers having the molecular formula `C_3H_6O`.
Strategy: first calculate the degree of unsaturation or DBEs:
`DBE=(sumn(v-2))/(2)+1`
`=(3(4-2)+6(1-2)+1(2-2))/(2)+1=1`
This means that various acyclic isomers of `C_3H_6O` contain just one double bond, i.e., `C=C` or `C=O`, in the following skeletons:
`C-C-C-O,C-C-O-C,C-underset(O)underset(|)(C)-C`

1 Answer

0 votes
by (65.9k points)
selected by
 
Best answer
(i). `CH_(2)=CH-CH_(2)-OH`
(ii). `CH_(3)CH=CH-OH`
(iii). `CH_(3)CH_(2)CH=O`
(iv). `CH_(2)=CH-O-CH_(3)`
(v). `CH_(2)=underset(OH)underset(|)(C)-CH_(3)`
(vi). `CH_(2)underset(O)underset(||)(C)CH_(3)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...