Question

ninety five milliliters of a mixture of a gaseous organic compound (A) and just sufficient amount of oxygen required for the complete combution yields on burning 40 ml of `CO_2` and 70 ml of water vapour along with 10 ml of nitrogen all volumes measured at the same temperature and pressure. Compound (A) contains carbon, hydrogen and nitrogen only as the consitituent elements. Calculate:
(a). The volume of `O_2` requried for complete combustion
(b). The molecular formula of (A).

Answer 1

`C_xH_yN_z+(x+(y)/(4))O_2rarrxCO_2+(y)/(2)H_2O+(z)/(2)N_2`
`a [(x+(y)/(4))s] xa [(y)/(2)xxa](z)/(2)xxaml`
According to question:
`{:(ax=40ml),(a(y)/(2)=70ml),(a(z)/(2)=10ml)]{:(becausex:(y)/(2):(z)/(2)-=4:7:1),or (2x:6,z=8:14:2),because2x=8:}}`
`{:(ax=40ml),(axx2=40ml),(a=20ml):}]{:(x=4),(becausex:y:z=4:14:2or2:7:1):}`
Formula `=C_2H_7Nbecausex=2`