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A compound contains `C=40%,O=53.5%`, and `H=6.5%` the empirical formula formula of the compound is:
A. `CH_2O`
B. `C_2H_4O`
C. `C_6H_(12)O_6`
D. `C_2H_4O_2`

1 Answer

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Best answer
Correct Answer - A
`{:(C,,H,,O),((40)/(12),,(6.5)/(1),,(53.5)/(16)),(3.33,,6.5,,3.34),(1,,2,,1):}`
`EF=CH_2O`

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