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The `pK_(a)` of `HCN` is 9.30. The pH of a solutin prepared by mixing `2.5` moles of `KCN` and `2.5` moles of `HCN` in water and making up the total volume to `500 mL` is
A. `9.3`
B. `7.3`
C. `10.3`
D. `8.3`

1 Answer

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Best answer
Correct Answer - D
`P^(H) = P^(ka) + "log" ("no. of moles of salt")/("no. of moles of acid")`

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