Correct Answer - D
`{:(TCl+NaOT ,rarr,NaCl+,T_(2)O),("Initial milli-moles 2",,,3.75),("milli-moles of remaining",,,NaOT = 1.75 "moles"):}`
`NaOTcon. = (1.75)/(40)`
`= 0.07 = 7 xx 10^(-2)`
`pOT = 2 - log 7`
`:. pT = 15.24 - 2 + "log" 7`
`= 13.24 + "log" 7`