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in Chemistry by (62.9k points)
A solution of glycine hydrochloride contains the chloride ion and the glycinium ion, `.^(+)NH_(3) - CH_(2) - COOH`, which is a diprotic acid,
`H_(3)N^(+) -CH_(2) - COOH + H_(2)O hArr`
`H_(3)N^(+) - CH_(2) - COO^(-) + H_(3)O^(+), K_(1) = 4.47 x10^(-3)`
`H_(3)N^(+) - CN_(2) - COO^(-) + H_(2)O hArr`
`H_(2)N - CH_(2) - COO^(-) + H_(3)O^(+), K_(2) = 1.66x10^(-10)`
Calculate pH of a `0.05 M` of glycine hydrochloride.
A. `1.89`
B. `2.52`
C. `8.91`
D. `9.18`

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1 Answer

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by (66.1k points)
Correct Answer - A
`(pH =pKa_(1) + pKa_(2))/(2)`

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