Question

`K_(sp)` of a salt `ZnCl_(2)` is `3.2 xx 10^(-8)` its `P^(H)` is
A. `2.3980`
B. `11.6020`
C. `2.6990`
D. Do not calculated exactly

Answer 1

Correct Answer - A
`ZnCl_(2) rarr underset(S)(Zn^(+2)) + underset(2S)(2Cl^(-))`
`K_(SP) = 4S^(3), S^(3) = 3.2 xx 10^(-8)`
`S = 2 xx 10^(-3) , P^(H) = 3 -2 "log" 2`
`S^(3) = 0.8 xx 10^(-8), S^(3) = 8 xx 10^(-9)`
`S = 2 xx 10^(-3), P^(H) = 3-2 "log" 2`
`= 3-03010 xx 2 , = 3 - 0.602`
`= 2.398`