Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
61 views
in Chemistry by (62.9k points)
closed by
Emission transitions in the Paschen series end at orbit n=3 and start from orbit n and can be represented as v=`3.29xx10^(15)(Hz)[1//3^(2)-1//n^(2)]`. Calculate the value of n if the transition is observed at 1285 nm. Find the region of the spectrum.

1 Answer

0 votes
by (66.0k points)
selected by
 
Best answer
`v=c/lambda=(3.0xx10^(8) ms^(-1))/(1285xx10^(-9) m)`
`=3.29xx10^(15)(1/3^(2)-1/n^(2))`
or `1/n^(2)=1/9-(3.0xx10^(8))/(1285xx10^(-9))xx1/(3.29xx10^(15))`
`=0.111-0.071=0.04=1/25`
or `n^(2)=25` or `n=5`
The radiation corresponding to `1285 nm` lies in the infrared region.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...