Question

What will be the minimum pressure required to compress `500dm^(3)` of air at 1bar to `200 dm^(3)` at `30^(@)C` ? .

Answer 1

`P_(1)= 1 "bar", P_(2)=?`
`V_(1)=500 dm^(3), V_(2)=200 dm^(3)`
`P_(1)V_(1)=P_(2)V_(2)`
`1xx500=P_(2)xx200`
or `P_(2)=(1xx500)/200=2.5 "bar"`