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The `K_(sp)` of `Mg(OH)_(2)` is `1xx10^(-12). 0.01M Mg^(2+)` will precipitate at the limiting pH of

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The `K_(sp)` of `Mg(OH)_(2)` is `1xx10^(-12). 0.01M Mg^(2+)` will precipitate at the limiting pH of
A. 3
B. 9
C. 12
D. 8
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Correct Answer - B
`[Mg^(2+][OH^(-)]^(2)= 1xx10^(-12)`,
`:. [OH^(-)]= sqrt((10^(-12))/(0.01))=10^(-5)`
or `pOH=5`
and thus `pH=9`
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