`CH_(3)underset(C(1-alpha))(CH_(2)COO)HhArrCH_(3)underset(Calpha)(CH_(2))COO^(-)+underset(Calpha)(H^(+))`

`K_(a)=1.32xx10^(-5)`

`=[(Ch_(3)CH_(2)COO^(-)][H^(+)])/([CH_(3)CH_(2)COOH])`

`(CalphaxxC alpha)/(C(-alpha))=Calpha^(2)" "(therefore1-alpha~~)`

`:. 0.05xxalpha^(2)=1.32xx10^(-5)`

`alpha = 1.63xx10^(-2)`

`pH= -Iog [H^(+)]= - Iog(C alpha)`

`= - Iog(0.05xx1.63xx10^(-2))=3.09`

In `0.01 NHCI: [H^(+)]= 0.01` and thus

`1.32xx10^(-5)= (Calphaxx0.01)/(C(1-alpha))= alphaxx0.1 , (.: 1-alpha ~~1)`

`alpha = 1.32xx10^(-3)`