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In the figure, ABCD is a square whose diagonals intersect at O. If AD = 10 cm, find the length of BD and CD ?

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Tn a square diagonal are equal and perpendicular bisectors of each other.

OD = 5 cm and OC = 5 cm.

CD2 = OD2 + OC2 = 52 + 52 = 50 cm

CD = \(\sqrt{50}\) = BD = \(5\sqrt{2}\) cm.

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