i. S = 12t – 2t2
Distance to the point when time is 1 second
= 12t – 2t2 = 12 × 1 – 2 × 12 = 12 – 2 = 10 m
Distance to the point when time is 5 second
= 12t – 2t2 = 12 × 5 – 2 × 52 = 60 – 50 = 10 m
Since the distance to the point till 6 seconds is positive. So the position of the point is on the right of P.
ii. Distance to the point when time is 6
second = 12t – 2t2 = 12 × 6 – 2 × 62 = 72 – 72 = 0
At the 6th second, the point is at P.
iii. Distance to the point when time is 7
second (after 6 sec)= 12t – 2t2 = 12 × 7 – 2 × 72
= 84 – 2 × 49 = 84 – 98 = -14 metres
This is a negative number, So the position of the point is on the left of P.