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Simplify \(\frac{-3}{2}+(\frac{-1}{2}\times\frac{-3}{4})+\frac{1}{2}\)

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\(\frac{-3}{2}+(\frac{-1}{2}\times\frac{-3}{4})+\frac{1}{2}\)

\(\frac{3}{2}+\frac{3}{8}+\frac{1}{2}\)

\(\frac{(-3\times4)+(3\times1)+(4\times1)}{8}\)

\(\frac{-12+3+4}{8}\) = \(\frac{-5}{8}\)

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