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in Hydrocarbons by (300 points)
Decreasing order of stability of: 1. \( CH _{3}- CH - CH _{3} \) 2. \( CH _{3}- CH - OCH _{3} \) \( 3 . CH _{3}- CH - CO - CH _{3} \) a. \( 1>2>3 \) b. \( 2>3>1 \) c. \( 3>1>2 \) d. \( 2>1>3 \)

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1 Answer

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Considering all given compounds are in cation from -

(i) CH3 - \(\overset{+}{CH}\) - CH3

(ii) CH3 - \(\overset{+}{CH}\) - OCH3

(iii) CH3 - \(\overset{+}{CH}\) - \(\overset{O}{\overset{||}{C}}\) - CH3

Compound (1), cation stabilized by hyper conjugation with  6 hydrogen

in compound (2), cation stabilized by hyper conjugation as well as by loan pair electron of oxygen.

CH3 - \(\overset{+}{CH}\) - O - CH3 ↔ CH3 - CH = \(\overset{+}{O}\) - CH3

it means compound (2) also stablilized by Resonance but in compound (3), the cation stabilized by hyperconjation with 3 hydrogen but destabilized by strong electron with drawing group \(\Big(-\overset{O}{\overset{||}{C}}-CH_3\Big)\) and we also know that Resonance is powerful

Than Hyper conjugation because of that compound (2) is more stabilized than compound (1)

Hence order of stability

2 > 1 > 3

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