Here, function f : A → B defined by , f(x) = 4x + 7, x∈R
Claim: f is one-one ?
Consider,
f(x) = f(y)
4x + 7 = 4y + 7
4x = 4y
x = y
Therefore, function f is one-one.
Now,
Claim: f is onto
let, y ∈ B , such that
y = f(x)
y = 4x + 7
4x = y - 7
x = (y - 7)/4
Since, y∈B
and x = (y - 7)/4 also belongs to B.
i.e., x ∈ B
Therefore, f is onto.