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Boiling point of water at 750 mm of Hg is 99.63 °C. How much sucrose must be added to 500 g of water so that it boils at 100 °C? (K = 0.52 K kg mol-1)

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Best answer

Given : 

Pressure = P = 750 mm Hg 

T0 = 273 + 99.63 = 372.63 K 

T0 = 273 + 100 = 373 K 

Kb = 0.52 K kg mol-1

Molar mass of sucrose (C12H22O11) = 342 × 10-3 kg mol-1

W1 = 500 g = 0.5 kg 

Mass of sucrose to be added = W2 = ? 

ΔTb = Tb – T0 

= 373 – 372.63 

= 0.37 K

∴ Mass of sucrose to be added = 121.7 × 10-3 kg 

= 121.7 g

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