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The concentration of solutions can be expressed in number of ways such that Normality, Molarity, Molality, Mole fractions, Strength, `%` by weight, `%` by volume and `%` by strength. The molarity of ionic compound is usually expressed as formality beacuse we use formula weight of ionic compound. Addition of water to a solution changes all these terms, however increase in temperature does not change molality, mole fraction and `%` by weight terms.
The weight of `Na_(2)CO_(3)` sample of `95%` purity required to neutralise `45.6 mL` of `0.235 N` acid is:
A. `0.60 g`
B. `0.80 g`
C. `0.40 g`
D. `0.20 g`

1 Answer

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Correct Answer - A
`because Meq.of Na_(2)CO_(3)=Meq.of H_(2)SO_(4)`
( for complete neutralisation)
Meq.of `Na_(2)CO_(3)=45.6xx0.235`
`therefore w=0.5679g`
`because 95 g` pure `Na_(2)CO_(3)` is to be taken then weighed sample `= 100 g`

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