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in Physics by (130 points)
edited by

The mean radius of the Earth's orbit around the Sun is 1.5 x 1011 m. The mean radius of the orbit of Mercury around the Sun is 6 × 1010 m. The mercury will rotate around the Sun in

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by (41.2k points)

T ∝ r3/2

\(\frac{T_m}{T_e} = (\frac{r_m}{r_e})^{3/2}\)

\((\frac{6 \times 10^{10}}{1.5 \times 10^{11}})^{3/2} = (\frac{2}{5})^{3/2}\) 

\(T_m = (\frac{2}{5})^{3/2}\)

\(T_e = (\frac{2}{5})^{3/2} \times 1 = (\frac{2}{5})^{3/2}\) years

+1 vote
by (425 points)

If the mean radius of the Earth's orbit around the Sun is 1.5 x 1011 m. The mean radius of the orbit of Mercury around the Sun is 6 × 1010 m. The mercury will rotate around the Sun in 1 YEAR. 

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