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The volume of `10` volume of `H_2O_2` required to liberate `500mL` of `O_2` at `STP is

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The volume of `10` volume of `H_2O_2` required to liberate `500mL` of `O_2` at `STP is
A. `25 mL`
B. `50 mL`
C. `100 mL`
D. `125 mL`
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1 Answer

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Correct Answer - B
`10` volume `H_(2)O_(2)` means 10 mL of `O_(2)` is produced at `STP` from `1` mL of 10vol `H_(2)O_(2)`
Hence `500` mL of `O_(2)` is produce at `STP` from
`500/10=50` mL of 10 vol `H_(2)O_(2)`
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