Question

`IE_(1), IE_(2)` and `IE_(3)` values are `100, 150` and `1500 eV` respectively. The element can be
A. `Na`
B. `B`
C. `Be`
D. `F`

Answer 1

Correct Answer - C
There is a high jump from `IE_(2)` to `IE_(3)`. Therefore, it is difficult to remove the 3rd valence electron. So, the element must be of group 2, e.g. `Be(2s^(2))`.