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If (a + ib) (c + id) (e + if) (g + ih) = A + iB, then show that:

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If (a + ib) (c + id) (e + if) (g + ih) = A + iB, then show that:

(a2 + b2) (c2 + d2) (e2 + f2) (g2 + h2) = A2 + B2.

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On squaring both sides, we obtain

(a2 + b2) (c2 + d2) (e2 + f2) (g2 + h2) = A2 + B2. Hence proved.

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