Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
190 views
in Trigonometry by (15 points)
edited by

If cos a=15/17 find sin2a

Please log in or register to answer this question.

1 Answer

0 votes
by (36.0k points)

cos a = \(\frac{15}{17}\)

∴ sin a = \(\sqrt{1-cos^2a}\)

\(\sqrt{1-(\frac{15}{17})^2}\)

\(\sqrt{\frac{289-225}{289}}\) 

\(\sqrt{\frac{64}{289}}\)

\(\frac{8}{17}\).

Now,

Sin2a = 2sina.cosa

= 2 x \(\frac{8}{17}\) x \(\frac{15}{17}\)

\(\frac{240}{289}\).

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...