Question

If the angle of triangle ABC are in the ratio 1:1:2, respectively (the largest angle being angle c) the the value of secA/cosecB-tanA/cotB

Answer 1

1x + 1x + 2x = 180°, x = 45°.
∠A, ∠B and ∠C are 45°, 45° and 90°resp.
secA/cosec B – tanA/cot B
= sec 45/cosec 45 – tan 45/cot 45
= √2/√2 – 1/1
= 1-1
= 0

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