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(b) a² + b² = 9  

 Explanation :- ∠OCB = 90° (OCB is a semicircle) 

Now, draw CD ⊥ OB. Then  CD = b, OD = a  and BD = 5 - a 

In Δ OCD, applying Pythagoras theorem we get

 ⇒ (OD)²  + (CD)² = (OC)² 

⇒ a² + b² = (3)² (OC = 3 units) 

∴ a² + b² = 9