Let x and y denote, respectively, the number of black and white sets and coloured sets made each week. Thus
x ≥ 0, y ≥ 0
Since the company can make at most 300 sets a week, therefore,
x + y ≤ 300
Weekly cost (in Rs) of manufacturing the set is
1800x + 2700y
and the company can spend upto Rs. 648000. Therefore,
1800x + 2700y ≤ 648000, i.e., or 2x + 3y ≤ 720
The total profit on x black and white sets and y colour sets is Rs (510x + 675y). Let Z = 510x + 675y . This is the objective function.
Thus, the mathematical formulation of the problem is
Maximise Z = 510x + 675y
subject to the constraints :
x + y ≥ 300
2x + 3y ≥ 720
x, y ≥ 0