Solve the following simultaneous equations. 27/(x - 2) + 31/(y + 3) = 85; 31/(x-2) + 27/(y+3) = 89

Question

Solve the following simultaneous equations.

\(\frac{27}{x-2} + \frac{31}{y+3} =85; \) \(\frac{31}{x-2} + \frac{27}{y+3} =89\)

27/(x - 2) + 31/(y + 3) = 85; 31/(x-2) + 27/(y+3) = 89

Answer 1

27/(x - 2) + 31/(y + 3) = 85;

The given simultaneous equations are

∴ Equations (i) and (ii) become

27p + 31q = 85 …(iii) 

31p + 27q = 89 …(iv)

Adding equations (iii) and (iv), we get

Subtracting equation (iv) from (iii), we get

Adding equations (v) and (vi), we get

Substituting p = 2 in equation (v), we get

Resubstituting the values of p and q, we get

\(\therefore\) (x, y) = (5/2, -2) is the solution of the given simultaneous equations.