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Find a positive value of m for which the coefficient of x2 in the expansion (1 + x)m is 6.

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It is known that (r + 1)th term, (Tr+1), in the binomial expansion of (a + b)n is given by

Assuming that x2 occurs in the (r + 1)th term of the expansion (1 +x)m, we obtain

Comparing the indices of x in x2 and in Tr + 1, we obtain r = 2

Therefore, the coefficient of x2 is mC2

It is given that the coefficient of x2 in the expansion (1 + x)m is 6.

Thus, the positive value of m , for which the coefficient of x2 in the expansion  (1 + x ) m is 6, is 4. 

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