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Seg PM is a median of APQR. If PQ = 40, PR = 42 and PM = 29, find QR.

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In ∆PQR, seg PM is the median. [Given] 

∴ M is the midpoint of side QR. 

∴ PQ2 + PR2 = 2 PM2 + 2 MR2  [Apollonius theorem]

∴ 402 + 422 = 2 (29)2 + 2 MR2 

∴ 1600 + 1764 = 2 (841) + 2 MR2 

∴ 3364 = 2 (841) + 2 MR2 

∴ 1682 = 841 +MR2 [Dividing both sides by 2]

∴ MR2 = 1682 – 841 

∴ MR2 = 841

∴ MR = \(\sqrt{841}\) [Taking square root of both sides]

= 29 units 

Now, QR = 2 MR [M is the midpoint of QR]

= 2 × 29 

∴ QR = 58 units

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